SOLVED: Scheduling multiple transitions (for the same voice at different times) at once

Jeff_Brown · 19 November 2023 18:23

Done, and pull request issued.

github.com/tidalcycles/Tidal

Functions for scheduling multiple upcoming changes to a voice in one shot.

tidalcycles:1.9-dev ← JeffreyBenjaminBrown:multi-schedule-1.9-dev

opened 06:22PM - 19 Nov 23 UTC

JeffreyBenjaminBrown

+121 -1

Adds two user-facing functions (and a number of coder-facing helper functions): … (1) `sched` is like `jumpIn`. Whereas `jumpIn` schedule one cycle to take over at some point in the future, `sched` schedules multiple things (and accepts fractional times). Here's an example: ``` do setcps 1 d1 $ s "[bd,numbers]" |* n (slow 8 $ run 8) sched 2 [ (2, s "lt*5"), (4, s "ht*4"), (6, s "hc*3") ] ``` In the above, voice `d1` will audibly count numbers as soon as it's evaluated. `d2` will wait two cycles, then start playing "lt*5" for two cycles, then "ht*4" for two cycles, and then "hc*3" from then on. (2) `schod` stands for `schedule modulo`. It is like `jumpMod`, except it lets you specify multiple changes (and accepts fractional times). The user specifies a divisor (probably a multile of 4 if you use straight time), and times scheduled are relative to the start of the most recent cycle that was divisible by the divisor. Here's an example: ``` do setcps 1 d1 $ s "[bd,numbers]" |* n (slow 8 $ run 8) schod 2 8 [ (2, s "lt*5"), (4, s "ht*4"), (6, s "hc*3"), (8, s "~ sn:1" ), (12, s "~ ~ sn:1" ), (16, silence) ] ``` Here the voice being scheduled is `d2` and the divisor is 8. Suppose the current cycle is 11. In that case, since 11 is equal to 3 mod 8, and 2 < 3, voice 2 will immediately start playing "lt*5". At cycle 12 (since 12 = 4 mod 8), it will switch to "ht*4". At cycle 14 it plays "hc*3". At cycle 16 it plays "~ sn:1". At cycle 20 it plays "~ ~ sn:1". Etc. Notice that the times being scheduled can be greater than the divisor. The divisor is only used to specify the start time.